search:bash execute command in variable相關網頁資料

- www.shellhacks.com
  
  HowTo : Execute a MySQL Command from a Linux BASH Shell? | MySQL
  
  Example : #!/bin/bash mysql -u root -pSeCrEt
  
  2025-11-17
  
  瀏覽：455
- stackoverflow.com
  
  Bash Script - Variable content as a command to run - Stack Overflow
  
  Your are probably looking for eval $var .
  
  2025-11-18
  
  瀏覽：1151

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How to set a BASH variable equal to the output from a command?

日期：2025-11-20

However, when I run the commands contained within the MOREF variable, I am able to get output....

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bash script how to execute a command from a variable - Stack ...

日期：2025-11-19

You want eval . It's evil. Or at least, dangerous. Read all about it at BashFAQ #48....

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bash - Execute command containing quotes from shell variable ...

日期：2025-11-21

Arrays are useful to keep your parameters whole: command=(su aUser -s /bin/ bash -c 'echo A'). and invoke it ......

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shell - BASH script - execute command with variable and store result ...

日期：2025-11-21

If you need to do some kind of transformation on the data first, you can "capture" output with the following ......

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shell - How to execute command stored in a variable? - Stack Overflow

日期：2025-11-20

This executes the output of the command, which e.g. in the case of ls -l will generate a message like "total" command ... BASH script - execute command with variable and store result....

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Bash shell script tip: Run commands from a variable - nixCraft

日期：2025-11-20

22 Apr 2007 ... There are many situations in which you may want to run different command in your shell script ......

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Variable as command; eval vs bash -c - Unix & Linux - Stack Exchange

日期：2025-11-14

13 Apr 2014 ... eval "$1" executes the command in the current script. It can set and use shell variables from the current ......

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linux - Execute a command stored in a variable - Super User

日期：2025-11-15

24 Nov 2013 ... I have a command stored in a variable. ... When I try to execute the above variable by typing $i it fails ... Long answer: it's because of the order in which bash parses the command line....

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