search:java math round up相關網頁資料

      • docs.oracle.com
        Translates a character array representation of a BigDecimal into a BigDecimal, accepting the same sequence of characters as the BigDecimal(String) constructor, while allowing a sub-array to be specified and with rounding according to the context settings.
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      • stackoverflow.com
        I have read a lot of stackoverflow questions but none seems to be working for me. i am using math.round() to round off. this is the code: class round{ public static void main(String ...
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    日期:2025-04-29
    Live @Sergey's solution but with integer division. double value = 23.8764367843; double rounded = (double) Math.round(value * 100) / 100; System.out.println(value +" rounded is "+ rounded); prints 23.8764367843 rounded is 23.88 EDIT: As Sergey points out,...
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    日期:2025-04-23
    ROUND_CEILING If the BigDecimal is positive, behave as for ROUND_UP; if negative, behave as for ROUND_DOWN. ROUND_DOWN Never increment the digit prior to a discarded fraction (i.e., truncate). ROUND_FLOOR If the BigDecimal is positive, behave as ......
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    日期:2025-04-30
    Math.ceil() is the correct function to call. I'm guessing a is an int , which would make a / 100 perform integer arithmetic. Try Math.ceil(a / 100.0) instead....
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    日期:2025-04-27
    How could I always round UP a double to an int, and never round it down. I know of Math.round(double) , but I want it to always round up. So if it ......
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    日期:2025-04-25
    int total = (int) Math.ceil(157/32);. Why does it still return 4? 157/32 ... 157/32 is int /int , which results in an int . Try using the double literal .... int total ......
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    日期:2025-04-30
    i just wrote a tiny method to count the number of page for cell phone ... To round up an integer division you can use import static java.lang....
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    日期:2025-04-28
    Why the result of 1/3=0 in java? ... My issue is that for some reason math.round seems to be always rounding .... Java Round up Any Number....
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    日期:2025-04-24
    int x = Math.round((729/10)); x = 72 OR int x = (int)Math.ceil((729/10)); x = 72 Whatever the number happens to be rounded, I always wanted ......