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日期:2026-04-20
但在參考書上有看到發電所的電功率(R不變)是用P=I2R,卻不能用P=V2/R,是因為後者所產生的能量會過大而導致電線熔掉的 ... 這只是P=IV與V=IR兩式演算而已...
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日期:2026-04-20
I originally thought that these were just different variable equations to the same power generation, but just learned they are not. P=IV is for the ......
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日期:2026-04-23
for electrical power generated go w/ P = IV, but for power loss due to heating etc. go w/ P = (I^2) R (i cant remember from where i read that for ......
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日期:2026-04-23
電磁標題:關於電功率的問題. 1:好奇小子榮譽點數2點(大學理工科系)張貼:2004-05-26 11:51:25:地點台灣台北. P=IV,P=I2R,P=V2/R 不是都相同ㄇ,為甚麼有些題目用 ......
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日期:2026-04-21
I was wondering what the different power equations are used for... P=IV, P=I2R, and P=V2/R I was solving for power loss and I noticed that ......
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日期:2026-04-24
Then you can use P=IV. You can do the same for the second equation too. You can use anyone of these anytime. FaroukYasser said: ↑....
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日期:2026-04-25
It is worth spending 5 minutes deriving different versions of the equations, i.e. start from P = IV and V = IR and deduce P = I2R = V2/R. Work towards completing a ......
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日期:2026-04-25
2008年2月11日 - Both can be used, But if you wanna use the i2r, that circuit must have the ... P power, U potential difference at the ends of the circuits, R resistence. ... Which of these is in correct in ohms law P=V2/R P=IV P=12R P=IR?...


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