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MySQL :: MySQL 5.0 Reference Manual :: 13.2.9 Subquery Syntax
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日期：2025-06-13
If you can't use subquery, you can use this; $sec1 = mysql_query("SELECT foto FROM profoto WHERE proje=$id"); if ($kyt1 = mysql_fetch_array($sec1)) {$dizi = $kyt1["foto"];} else {$dizi="0";} while ($kyt1 = mysql_fetch_array($sec1)) {$dizi = $dizi . "," . ...看更多
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