一、反三角函數之定義

一、反三角函數之定義

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日期:2024-05-29
7. Prove that tan−1 x+1 x −1 +tan−1 x =c, a constant, and find c. 解答: Let y =tan−1 x+1 x −1 +tan−1 x, and then dy dx = 1 1+(x+1 x −1)2 ⋅ x −1−x −1 (x −1) 2 + 1 1+x2 = −2 (x −1)2 +(x+1)2 + 1 x2 +1 =0. Therefore, we can prove that y =tan−1 x+1 x −1 +tan−1 ....看更多